17+3(z-2)-11=7(Z+2)+14

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Solution for 17+3(z-2)-11=7(Z+2)+14 equation: 


Simplifying
17 + 3(z + -2) + -11 = 7(Z + 2) + 14

Reorder the terms:
17 + 3(-2 + z) + -11 = 7(Z + 2) + 14
17 + (-2 * 3 + z * 3) + -11 = 7(Z + 2) + 14
17 + (-6 + 3z) + -11 = 7(Z + 2) + 14

Reorder the terms:
17 + -6 + -11 + 3z = 7(Z + 2) + 14

Combine like terms: 17 + -6 = 11
11 + -11 + 3z = 7(Z + 2) + 14

Combine like terms: 11 + -11 = 0
0 + 3z = 7(Z + 2) + 14
3z = 7(Z + 2) + 14

Reorder the terms:
3z = 7(2 + Z) + 14
3z = (2 * 7 + Z * 7) + 14
3z = (14 + 7Z) + 14

Reorder the terms:
3z = 14 + 14 + 7Z

Combine like terms: 14 + 14 = 28
3z = 28 + 7Z

Solving
3z = 28 + 7Z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Divide each side by '3'.
z = 9.333333333 + 2.333333333Z

Simplifying
z = 9.333333333 + 2.333333333Z

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