17+3(z+-2)+-11z=-7(z+2)+14

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Solution for 17+3(z+-2)+-11z=-7(z+2)+14 equation:



17+3(z+-2)+-11z=-7(z+2)+14
We move all terms to the left:
17+3(z+-2)+-11z-(-7(z+2)+14)=0
We add all the numbers together, and all the variables
3(z-2)-11z-(-7(z+2)+14)+17+=0
We add all the numbers together, and all the variables
-11z+3(z-2)-(-7(z+2)+14)=0
We multiply parentheses
-11z+3z-(-7(z+2)+14)-6=0
We calculate terms in parentheses: -(-7(z+2)+14), so:
-7(z+2)+14
We multiply parentheses
-7z-14+14
We add all the numbers together, and all the variables
-7z
Back to the equation:
-(-7z)
We add all the numbers together, and all the variables
-8z-(-7z)-6=0
We get rid of parentheses
-8z+7z-6=0
We add all the numbers together, and all the variables
-1z-6=0
We move all terms containing z to the left, all other terms to the right
-z=6
z=6/-1
z=-6

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