17+20j=3(j+17)

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Solution for 17+20j=3(j+17) equation: 



17+20j=3(j+17)

We move all terms to the left:

17+20j-(3(j+17))=0



We calculate terms in parentheses: -(3(j+17)), so:

3(j+17)

We multiply parentheses

3j+51

Back to the equation:

-(3j+51)



We get rid of parentheses

20j-3j-51+17=0

We add all the numbers together, and all the variables

17j-34=0

We move all terms containing j to the left, all other terms to the right

17j=34

j=34/17

j=2

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