17(t-6)+4t=7(3t+2)-13

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Solution for 17(t-6)+4t=7(3t+2)-13 equation: 



17(t-6)+4t=7(3t+2)-13

We move all terms to the left:

17(t-6)+4t-(7(3t+2)-13)=0

We add all the numbers together, and all the variables

4t+17(t-6)-(7(3t+2)-13)=0

We multiply parentheses

4t+17t-(7(3t+2)-13)-102=0



We calculate terms in parentheses: -(7(3t+2)-13), so:

7(3t+2)-13

We multiply parentheses

21t+14-13

We add all the numbers together, and all the variables

21t+1

Back to the equation:

-(21t+1)



We add all the numbers together, and all the variables

21t-(21t+1)-102=0

We get rid of parentheses

21t-21t-1-102=0

We add all the numbers together, and all the variables

-103!=0

There is no solution for this equation

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