17(3d-4)+100=66

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Solution for 17(3d-4)+100=66 equation:



17(3d-4)+100=66
We move all terms to the left:
17(3d-4)+100-(66)=0
We add all the numbers together, and all the variables
17(3d-4)+34=0
We multiply parentheses
51d-68+34=0
We add all the numbers together, and all the variables
51d-34=0
We move all terms containing d to the left, all other terms to the right
51d=34
d=34/51
d=2/3

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