16y2+16y+4=(y)2

Solution for 16y2+16y+4=(y)2 equation:

16y^2+16y+4=(y)2

We move all terms to the left:

16y^2+16y+4-((y)2)=0

determiningTheFunctionDomain
16y^2+16y-y2+4=0

We add all the numbers together, and all the variables

15y^2+16y+4=0

a = 15; b = 16; c = +4;
Δ = b2-4ac
Δ = 162-4·15·4
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4}{2*15}=\frac{-20}{30}
=-2/3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4}{2*15}=\frac{-12}{30}
=-2/5
$