16y-(4y-6)=18

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Solution for 16y-(4y-6)=18 equation: 



16y-(4y-6)=18

We move all terms to the left:

16y-(4y-6)-(18)=0

We get rid of parentheses

16y-4y+6-18=0

We add all the numbers together, and all the variables

12y-12=0

We move all terms containing y to the left, all other terms to the right

12y=12

y=12/12

y=1

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