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16x^2=12x
We move all terms to the left:
16x^2-(12x)=0
a = 16; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·16·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*16}=\frac{0}{32} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*16}=\frac{24}{32} =3/4 $
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