16x2-8x=24

Solution for 16x2-8x=24 equation:

16x^2-8x=24

We move all terms to the left:

16x^2-8x-(24)=0

a = 16; b = -8; c = -24;
Δ = b2-4ac
Δ = -82-4·16·(-24)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-40}{2*16}=\frac{-32}{32}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+40}{2*16}=\frac{48}{32}
=1+1/2
$