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16x^2-77x+20=0
a = 16; b = -77; c = +20;
Δ = b2-4ac
Δ = -772-4·16·20
Δ = 4649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-77)-\sqrt{4649}}{2*16}=\frac{77-\sqrt{4649}}{32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-77)+\sqrt{4649}}{2*16}=\frac{77+\sqrt{4649}}{32} $
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