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16x^2-361=0
a = 16; b = 0; c = -361;
Δ = b2-4ac
Δ = 02-4·16·(-361)
Δ = 23104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{23104}=152$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-152}{2*16}=\frac{-152}{32} =-4+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+152}{2*16}=\frac{152}{32} =4+3/4 $
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