16x2-26x-10=0

Solution for 16x2-26x-10=0 equation:

16x^2-26x-10=0

a = 16; b = -26; c = -10;
Δ = b2-4ac
Δ = -262-4·16·(-10)
Δ = 1316
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1316}=\sqrt{4*329}=\sqrt{4}*\sqrt{329}=2\sqrt{329}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2\sqrt{329}}{2*16}=\frac{26-2\sqrt{329}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2\sqrt{329}}{2*16}=\frac{26+2\sqrt{329}}{32}
$