16x2-236x+274=0

Solution for 16x2-236x+274=0 equation:

16x^2-236x+274=0

a = 16; b = -236; c = +274;
Δ = b2-4ac
Δ = -2362-4·16·274
Δ = 38160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{38160}=\sqrt{144*265}=\sqrt{144}*\sqrt{265}=12\sqrt{265}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-236)-12\sqrt{265}}{2*16}=\frac{236-12\sqrt{265}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-236)+12\sqrt{265}}{2*16}=\frac{236+12\sqrt{265}}{32}
$