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16x^2-12x=54
We move all terms to the left:
16x^2-12x-(54)=0
a = 16; b = -12; c = -54;
Δ = b2-4ac
Δ = -122-4·16·(-54)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-60}{2*16}=\frac{-48}{32} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+60}{2*16}=\frac{72}{32} =2+1/4 $
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