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16x^2-112x=0
a = 16; b = -112; c = 0;
Δ = b2-4ac
Δ = -1122-4·16·0
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12544}=112$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-112)-112}{2*16}=\frac{0}{32} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-112)+112}{2*16}=\frac{224}{32} =7 $
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