16x-9(x+1)=5(x-2)

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Solution for 16x-9(x+1)=5(x-2) equation: 



16x-9(x+1)=5(x-2)

We move all terms to the left:

16x-9(x+1)-(5(x-2))=0

We multiply parentheses

16x-9x-(5(x-2))-9=0



We calculate terms in parentheses: -(5(x-2)), so:

5(x-2)

We multiply parentheses

5x-10

Back to the equation:

-(5x-10)



We add all the numbers together, and all the variables

7x-(5x-10)-9=0

We get rid of parentheses

7x-5x+10-9=0

We add all the numbers together, and all the variables

2x+1=0

We move all terms containing x to the left, all other terms to the right

2x=-1

x=-1/2

x=-1/2

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