16x-12-24+4=4+16x-12(1+2x)

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Solution for 16x-12-24+4=4+16x-12(1+2x) equation: 



16x-12-24+4=4+16x-12(1+2x)

We move all terms to the left:

16x-12-24+4-(4+16x-12(1+2x))=0

We add all the numbers together, and all the variables

16x-(4+16x-12(2x+1))-12-24+4=0

We add all the numbers together, and all the variables

16x-(4+16x-12(2x+1))-32=0



We calculate terms in parentheses: -(4+16x-12(2x+1)), so:

4+16x-12(2x+1)

determiningTheFunctionDomain
16x-12(2x+1)+4

We multiply parentheses

16x-24x-12+4

We add all the numbers together, and all the variables

-8x-8

Back to the equation:

-(-8x-8)



We get rid of parentheses

16x+8x+8-32=0

We add all the numbers together, and all the variables

24x-24=0

We move all terms containing x to the left, all other terms to the right

24x=24

x=24/24

x=1

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