16x+7(1-x)=-4(x-4)

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Solution for 16x+7(1-x)=-4(x-4) equation:



16x+7(1-x)=-4(x-4)
We move all terms to the left:
16x+7(1-x)-(-4(x-4))=0
We add all the numbers together, and all the variables
16x+7(-1x+1)-(-4(x-4))=0
We multiply parentheses
16x-7x-(-4(x-4))+7=0
We calculate terms in parentheses: -(-4(x-4)), so:
-4(x-4)
We multiply parentheses
-4x+16
Back to the equation:
-(-4x+16)
We add all the numbers together, and all the variables
9x-(-4x+16)+7=0
We get rid of parentheses
9x+4x-16+7=0
We add all the numbers together, and all the variables
13x-9=0
We move all terms containing x to the left, all other terms to the right
13x=9
x=9/13
x=9/13

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