16x+40=2(70-2x)

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Solution for 16x+40=2(70-2x) equation: 



16x+40=2(70-2x)

We move all terms to the left:

16x+40-(2(70-2x))=0

We add all the numbers together, and all the variables

16x-(2(-2x+70))+40=0



We calculate terms in parentheses: -(2(-2x+70)), so:

2(-2x+70)

We multiply parentheses

-4x+140

Back to the equation:

-(-4x+140)



We get rid of parentheses

16x+4x-140+40=0

We add all the numbers together, and all the variables

20x-100=0

We move all terms containing x to the left, all other terms to the right

20x=100

x=100/20

x=5

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