16x(4x-3)=87

Solution for 16x(4x-3)=87 equation:

16x(4x-3)=87

We move all terms to the left:

16x(4x-3)-(87)=0

We multiply parentheses

64x^2-48x-87=0

a = 64; b = -48; c = -87;
Δ = b2-4ac
Δ = -482-4·64·(-87)
Δ = 24576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{24576}=\sqrt{4096*6}=\sqrt{4096}*\sqrt{6}=64\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-64\sqrt{6}}{2*64}=\frac{48-64\sqrt{6}}{128}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+64\sqrt{6}}{2*64}=\frac{48+64\sqrt{6}}{128}
$