16x(1/32)-x=4-3x+1

Solution for 16x(1/32)-x=4-3x+1 equation:

16x(1/32)-x=4-3x+1

We move all terms to the left:

16x(1/32)-x-(4-3x+1)=0

We add all the numbers together, and all the variables

16x(+1/32)-x-(-3x+5)=0

We add all the numbers together, and all the variables

-1x+16x(+1/32)-(-3x+5)=0

We multiply parentheses

16x^2-1x-(-3x+5)=0

We get rid of parentheses

16x^2-1x+3x-5=0

We add all the numbers together, and all the variables

16x^2+2x-5=0

a = 16; b = 2; c = -5;
Δ = b2-4ac
Δ = 22-4·16·(-5)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-18}{2*16}=\frac{-20}{32}
=-5/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+18}{2*16}=\frac{16}{32}
=1/2
$