16w2=121

Solution for 16w2=121 equation:

16w^2=121

We move all terms to the left:

16w^2-(121)=0

a = 16; b = 0; c = -121;
Δ = b2-4ac
Δ = 02-4·16·(-121)
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-88}{2*16}=\frac{-88}{32}
=-2+3/4
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+88}{2*16}=\frac{88}{32}
=2+3/4
$