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16t^2-676=0
a = 16; b = 0; c = -676;
Δ = b2-4ac
Δ = 02-4·16·(-676)
Δ = 43264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{43264}=208$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-208}{2*16}=\frac{-208}{32} =-6+1/2 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+208}{2*16}=\frac{208}{32} =6+1/2 $
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