16t2-484=0

Solution for 16t2-484=0 equation:

16t^2-484=0

a = 16; b = 0; c = -484;
Δ = b2-4ac
Δ = 02-4·16·(-484)
Δ = 30976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{30976}=176$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-176}{2*16}=\frac{-176}{32}
=-5+1/2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+176}{2*16}=\frac{176}{32}
=5+1/2
$