16t2+72t+81=0

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Solution for 16t2+72t+81=0 equation: 



16t^2+72t+81=0

a = 16; b = 72; c = +81;
Δ = b2-4ac
Δ = 722-4·16·81
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{-72}{32}=-2+1/4$

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