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16m^2-85m+112=3m
We move all terms to the left:
16m^2-85m+112-(3m)=0
We add all the numbers together, and all the variables
16m^2-88m+112=0
a = 16; b = -88; c = +112;
Δ = b2-4ac
Δ = -882-4·16·112
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-88)-24}{2*16}=\frac{64}{32} =2 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-88)+24}{2*16}=\frac{112}{32} =3+1/2 $
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