16b2+60b-100=b

Solution for 16b2+60b-100=b equation:

16b^2+60b-100=b

We move all terms to the left:

16b^2+60b-100-(b)=0

We add all the numbers together, and all the variables

16b^2+59b-100=0

a = 16; b = 59; c = -100;
Δ = b2-4ac
Δ = 592-4·16·(-100)
Δ = 9881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(59)-\sqrt{9881}}{2*16}=\frac{-59-\sqrt{9881}}{32}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(59)+\sqrt{9881}}{2*16}=\frac{-59+\sqrt{9881}}{32}
$