16=4+3(z+2)

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Solution for 16=4+3(z+2) equation: 



16=4+3(z+2)

We move all terms to the left:

16-(4+3(z+2))=0



We calculate terms in parentheses: -(4+3(z+2)), so:

4+3(z+2)

determiningTheFunctionDomain
3(z+2)+4

We multiply parentheses

3z+6+4

We add all the numbers together, and all the variables

3z+10

Back to the equation:

-(3z+10)



We get rid of parentheses

-3z-10+16=0

We add all the numbers together, and all the variables

-3z+6=0

We move all terms containing z to the left, all other terms to the right

-3z=-6

z=-6/-3

z=+2

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