16=3(n+2)-n

Solution for 16=3(n+2)-n equation:

16=3(n+2)-n

We move all terms to the left:

16-(3(n+2)-n)=0


We calculate terms in parentheses: -(3(n+2)-n), so:

3(n+2)-n

We add all the numbers together, and all the variables

-1n+3(n+2)

We multiply parentheses

-1n+3n+6

We add all the numbers together, and all the variables

2n+6

Back to the equation:

-(2n+6)


We get rid of parentheses

-2n-6+16=0

We add all the numbers together, and all the variables

-2n+10=0

We move all terms containing n to the left, all other terms to the right

-2n=-10

n=-10/-2

n=+5