16=2(x-2)4x

Solution for 16=2(x-2)4x equation:

16=2(x-2)4x

We move all terms to the left:

16-(2(x-2)4x)=0


We calculate terms in parentheses: -(2(x-2)4x), so:

2(x-2)4x

We multiply parentheses

8x^2-16x

Back to the equation:

-(8x^2-16x)


We get rid of parentheses

-8x^2+16x+16=0

a = -8; b = 16; c = +16;
Δ = b2-4ac
Δ = 162-4·(-8)·16
Δ = 768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{768}=\sqrt{256*3}=\sqrt{256}*\sqrt{3}=16\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16\sqrt{3}}{2*-8}=\frac{-16-16\sqrt{3}}{-16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16\sqrt{3}}{2*-8}=\frac{-16+16\sqrt{3}}{-16}
$