16=1/3(9x-36)+4x

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Solution for 16=1/3(9x-36)+4x equation: 



16=1/3(9x-36)+4x

We move all terms to the left:

16-(1/3(9x-36)+4x)=0



Domain of the equation: 3(9x-36)+4x)!=0

x∈R



We multiply all the terms by the denominator


-(1+16*3(9x-36)+4x)=0



We calculate terms in parentheses: -(1+16*3(9x-36)+4x), so:

1+16*3(9x-36)+4x

determiningTheFunctionDomain
16*3(9x-36)+4x+1

We add all the numbers together, and all the variables

4x+16*3(9x-36)+1

Wy multiply elements

4x+48x(9+1

Back to the equation:

-(4x+48x(9+1)



We add all the numbers together, and all the variables

-(4x+48x10=0

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