16=1/2(7z-6)

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Solution for 16=1/2(7z-6) equation: 



16=1/2(7z-6)

We move all terms to the left:

16-(1/2(7z-6))=0



Domain of the equation: 2(7z-6))!=0

z∈R



We multiply all the terms by the denominator


-(1+16*2(7z-6))=0



We calculate terms in parentheses: -(1+16*2(7z-6)), so:

1+16*2(7z-6)

determiningTheFunctionDomain
16*2(7z-6)+1

Wy multiply elements

32z(7+1

Back to the equation:

-(32z(7+1)



We add all the numbers together, and all the variables

-(32z8=0

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