16=1/2(6+2x)12

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Solution for 16=1/2(6+2x)12 equation: 



16=1/2(6+2x)12

We move all terms to the left:

16-(1/2(6+2x)12)=0



Domain of the equation: 2(6+2x)12)!=0

x∈R



We add all the numbers together, and all the variables

-(1/2(2x+6)12)+16=0

We multiply all the terms by the denominator


-(1+16*2(2x+6)12)=0



We calculate terms in parentheses: -(1+16*2(2x+6)12), so:

1+16*2(2x+6)12

determiningTheFunctionDomain
16*2(2x+6)12+1

Wy multiply elements

32x(2+1

Back to the equation:

-(32x(2+1)



We add all the numbers together, and all the variables

-(32x3=0

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