160=(180(n-2))/n

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Solution for 160=(180(n-2))/n equation: 



160=(180(n-2))/n

We move all terms to the left:

160-((180(n-2))/n)=0



Domain of the equation: n)!=0

n!=0/1

n!=0

n∈R



We multiply all the terms by the denominator


-((180(n-2))+160*n)=0



We calculate terms in parentheses: -((180(n-2))+160*n), so:

(180(n-2))+160*n

We add all the numbers together, and all the variables

160n+(180(n-2))



We calculate terms in parentheses: +(180(n-2)), so:

180(n-2)

We multiply parentheses

180n-360

Back to the equation:

+(180n-360)



We get rid of parentheses

160n+180n-360

We add all the numbers together, and all the variables

340n-360

Back to the equation:

-(340n-360)



We get rid of parentheses

-340n+360=0

We move all terms containing n to the left, all other terms to the right

-340n=-360

n=-360/-340

n=1+1/17

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