1605+4(3-x)=2011

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Solution for 1605+4(3-x)=2011 equation: 



1605+4(3-x)=2011

We move all terms to the left:

1605+4(3-x)-(2011)=0

We add all the numbers together, and all the variables

4(-1x+3)+1605-2011=0

We add all the numbers together, and all the variables

4(-1x+3)-406=0

We multiply parentheses

-4x+12-406=0

We add all the numbers together, and all the variables

-4x-394=0

We move all terms containing x to the left, all other terms to the right

-4x=394

x=394/-4

x=-98+1/2

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