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1600=16t^2
We move all terms to the left:
1600-(16t^2)=0
a = -16; b = 0; c = +1600;
Δ = b2-4ac
Δ = 02-4·(-16)·1600
Δ = 102400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{102400}=320$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-320}{2*-16}=\frac{-320}{-32} =+10 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+320}{2*-16}=\frac{320}{-32} =-10 $
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