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16/3y-5/y=
We move all terms to the left:
16/3y-5/y-()=0
Domain of the equation: 3y!=0
y!=0/3
y!=0
y∈R
Domain of the equation: y!=0We add all the numbers together, and all the variables
y∈R
16/3y-5/y=0
We calculate fractions
16y/3y^2+(-15y)/3y^2=0
We multiply all the terms by the denominator
16y+(-15y)=0
We get rid of parentheses
16y-15y=0
We add all the numbers together, and all the variables
y=0
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