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16.5-13.8x+2.5x^2=0
a = 2.5; b = -13.8; c = +16.5;
Δ = b2-4ac
Δ = -13.82-4·2.5·16.5
Δ = 25.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13.8)-\sqrt{25.44}}{2*2.5}=\frac{13.8-\sqrt{25.44}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13.8)+\sqrt{25.44}}{2*2.5}=\frac{13.8+\sqrt{25.44}}{5} $
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