16-4i/3i

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Solution for 16-4i/3i equation:


i in (-oo:+oo)

16-(((4*i)/3)*i) = 0

(-4/3)*i^2+16 = 0

-4/3*i^2 = -16 // : -4/3

i^2 = 12

i^2 = 12 // ^ 1/2

abs(i) = 2*3^(1/2)

i = 2*3^(1/2) or i = -(2*3^(1/2))

i in { 2*3^(1/2), -(2*3^(1/2)) }

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