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16-3x(x-3)=9x+176
We move all terms to the left:
16-3x(x-3)-(9x+176)=0
We multiply parentheses
-3x^2+9x-(9x+176)+16=0
We get rid of parentheses
-3x^2+9x-9x-176+16=0
We add all the numbers together, and all the variables
-3x^2-160=0
a = -3; b = 0; c = -160;
Δ = b2-4ac
Δ = 02-4·(-3)·(-160)
Δ = -1920
Delta is less than zero, so there is no solution for the equation
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