16-2u-4/3u=18

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Solution for 16-2u-4/3u=18 equation: 



16-2u-4/3u=18

We move all terms to the left:

16-2u-4/3u-(18)=0



Domain of the equation: 3u!=0

u!=0/3

u!=0

u∈R



We add all the numbers together, and all the variables

-2u-4/3u-2=0

We multiply all the terms by the denominator


-2u*3u-2*3u-4=0

Wy multiply elements

-6u^2-6u-4=0

a = -6; b = -6; c = -4;
Δ = b2-4ac
Δ = -62-4·(-6)·(-4)
Δ = -60
Delta is less than zero, so there is no solution for the equation

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