16-2t=(3/2)t+9

Solution for 16-2t=(3/2)t+9 equation:

16-2t=(3/2)t+9

We move all terms to the left:

16-2t-((3/2)t+9)=0


Domain of the equation: 2)t+9)!=0

t!=0/1

t!=0

t∈R


We add all the numbers together, and all the variables

-2t-((+3/2)t+9)+16=0

We multiply all the terms by the denominator


-2t*2)t+9)-((+16*2)t+9)+3=0

We add all the numbers together, and all the variables

-2t*2)t+9)-(32t+9)+3=0

Wy multiply elements

-4t^2=0

a = -4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-4)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{-8}=0$