16-2(2u-3)=7u

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Solution for 16-2(2u-3)=7u equation: 



16-2(2u-3)=7u

We move all terms to the left:

16-2(2u-3)-(7u)=0

We add all the numbers together, and all the variables

-7u-2(2u-3)+16=0

We multiply parentheses

-7u-4u+6+16=0

We add all the numbers together, and all the variables

-11u+22=0

We move all terms containing u to the left, all other terms to the right

-11u=-22

u=-22/-11

u=+2

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