16-(-3x-4)=2(-18x+1)-4x

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Solution for 16-(-3x-4)=2(-18x+1)-4x equation: 



16-(-3x-4)=2(-18x+1)-4x

We move all terms to the left:

16-(-3x-4)-(2(-18x+1)-4x)=0

We get rid of parentheses

3x-(2(-18x+1)-4x)+4+16=0



We calculate terms in parentheses: -(2(-18x+1)-4x), so:

2(-18x+1)-4x

We add all the numbers together, and all the variables

-4x+2(-18x+1)

We multiply parentheses

-4x-36x+2

We add all the numbers together, and all the variables

-40x+2

Back to the equation:

-(-40x+2)



We add all the numbers together, and all the variables

3x-(-40x+2)+20=0

We get rid of parentheses

3x+40x-2+20=0

We add all the numbers together, and all the variables

43x+18=0

We move all terms containing x to the left, all other terms to the right

43x=-18

x=-18/43

x=-18/43

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