16+4x=4/x

Solution for 16+4x=4/x equation:

16+4x=4/x

We move all terms to the left:

16+4x-(4/x)=0


Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

4x-(+4/x)+16=0

We get rid of parentheses

4x-4/x+16=0

We multiply all the terms by the denominator


4x*x+16*x-4=0

We add all the numbers together, and all the variables

16x+4x*x-4=0

Wy multiply elements

4x^2+16x-4=0

a = 4; b = 16; c = -4;
Δ = b2-4ac
Δ = 162-4·4·(-4)
Δ = 320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{320}=\sqrt{64*5}=\sqrt{64}*\sqrt{5}=8\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-8\sqrt{5}}{2*4}=\frac{-16-8\sqrt{5}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+8\sqrt{5}}{2*4}=\frac{-16+8\sqrt{5}}{8}
$