16+3y-y2=2

Solution for 16+3y-y2=2 equation:

16+3y-y2=2

We move all terms to the left:

16+3y-y2-(2)=0

We add all the numbers together, and all the variables

-1y^2+3y+14=0

a = -1; b = 3; c = +14;
Δ = b2-4ac
Δ = 32-4·(-1)·14
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{65}}{2*-1}=\frac{-3-\sqrt{65}}{-2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{65}}{2*-1}=\frac{-3+\sqrt{65}}{-2}
$