16+2n=3(n+6)-2

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Solution for 16+2n=3(n+6)-2 equation: 



16+2n=3(n+6)-2

We move all terms to the left:

16+2n-(3(n+6)-2)=0



We calculate terms in parentheses: -(3(n+6)-2), so:

3(n+6)-2

We multiply parentheses

3n+18-2

We add all the numbers together, and all the variables

3n+16

Back to the equation:

-(3n+16)



We get rid of parentheses

2n-3n-16+16=0

We add all the numbers together, and all the variables

-n=0

n=0/-1

n=0

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