16(x+3)=4(4x+2)+40

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Solution for 16(x+3)=4(4x+2)+40 equation: 


Simplifying
16(x + 3) = 4(4x + 2) + 40

Reorder the terms:
16(3 + x) = 4(4x + 2) + 40
(3 * 16 + x * 16) = 4(4x + 2) + 40
(48 + 16x) = 4(4x + 2) + 40

Reorder the terms:
48 + 16x = 4(2 + 4x) + 40
48 + 16x = (2 * 4 + 4x * 4) + 40
48 + 16x = (8 + 16x) + 40

Reorder the terms:
48 + 16x = 8 + 40 + 16x

Combine like terms: 8 + 40 = 48
48 + 16x = 48 + 16x

Add '-48' to each side of the equation.
48 + -48 + 16x = 48 + -48 + 16x

Combine like terms: 48 + -48 = 0
0 + 16x = 48 + -48 + 16x
16x = 48 + -48 + 16x

Combine like terms: 48 + -48 = 0
16x = 0 + 16x
16x = 16x

Add '-16x' to each side of the equation.
16x + -16x = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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