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16(x+1)-2(x-3)=15
We move all terms to the left:
16(x+1)-2(x-3)-(15)=0
We multiply parentheses
16x-2x+16+6-15=0
We add all the numbers together, and all the variables
14x+7=0
We move all terms containing x to the left, all other terms to the right
14x=-7
x=-7/14
x=-1/2
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