16(x)+32=20(x)+4

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Solution for 16(x)+32=20(x)+4 equation: 



16(x)+32=20(x)+4

We move all terms to the left:

16(x)+32-(20(x)+4)=0

We get rid of parentheses

16x-20x-4+32=0

We add all the numbers together, and all the variables

-4x+28=0

We move all terms containing x to the left, all other terms to the right

-4x=-28

x=-28/-4

x=+7

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